What are the solutions to the equation x(x+5)-2x=28 ?

The solutions to the equation x(x+5)-2x=28 are x=4,x=-7

Find the zeros of x(x+5)-2x=28

The zeros of x(x+5)-2x=28 are x=4,x=-7

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x (x + 5) - 2 x = 28

x = 4, x = - 7

Solution steps

x (x + 5) - 2 x = 28

Expand

x (x + 5) - 2 x : x^{2} + 3 x

x^{2} + 3 x = 28

Move

28

to the left side

x^{2} + 3 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 28) = 11

x_{1, 2} = \frac{- 3 \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 11}{2 \cdot 1}, x_{2} = \frac{- 3 - 11}{2 \cdot 1}

x = \frac{- 3 + 11}{2 \cdot 1} : 4

x = \frac{- 3 - 11}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 4, x = - 7

x (x - 11) + 28 = 0

3 p^{2} + 36 = 0

7 (x - 3)^{2} - 52 = 11

2 (x - 4)^{2} + 7 = 13

(5 x - 11)^{2} + 6 = 150

What are the solutions to the equation x(x+5)-2x=28 ?
The solutions to the equation x(x+5)-2x=28 are x=4,x=-7
Find the zeros of x(x+5)-2x=28
The zeros of x(x+5)-2x=28 are x=4,x=-7