What are the solutions to the equation 3p^2+36=0 ?

The solutions to the equation 3p^2+36=0 are p=2sqrt(3)i,p=-2sqrt(3)i

Find the zeros of 3p^2+36=0

The zeros of 3p^2+36=0 are p=2sqrt(3)i,p=-2sqrt(3)i

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3 p^{2} + 36 = 0

p = 23 i, p = - 23 i

Solution steps

3 p^{2} + 36 = 0

Move

36

to the right side

3 p^{2} = - 36

Divide both sides by

3

p^{2} = - 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = - 12, p = - - 12

- 12 = 23 i

- - 12 = - 23 i

p = 23 i, p = - 23 i

7 (x - 3)^{2} - 52 = 11

2 (x - 4)^{2} + 7 = 13

(5 x - 11)^{2} + 6 = 150

x, y (x^{2} + 1) = 1

- x^{2} + 2 x + 63 = 0

What are the solutions to the equation 3p^2+36=0 ?
The solutions to the equation 3p^2+36=0 are p=2sqrt(3)i,p=-2sqrt(3)i
Find the zeros of 3p^2+36=0
The zeros of 3p^2+36=0 are p=2sqrt(3)i,p=-2sqrt(3)i