What are the solutions to the equation n(n-7)=260 ?

The solutions to the equation n(n-7)=260 are n=20,n=-13

Find the zeros of n(n-7)=260

The zeros of n(n-7)=260 are n=20,n=-13

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n (n - 7) = 260

n = 20, n = - 13

Solution steps

n (n - 7) = 260

Expand

n (n - 7) : n^{2} - 7 n

n^{2} - 7 n = 260

Move

260

to the left side

n^{2} - 7 n - 260 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 260 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 260) = 33

n_{1, 2} = \frac{- ( - 7 ) \pm 33}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 7 ) + 33}{2 \cdot 1}, n_{2} = \frac{- ( - 7 ) - 33}{2 \cdot 1}

n = \frac{- ( - 7 ) + 33}{2 \cdot 1} : 20

n = \frac{- ( - 7 ) - 33}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

n = 20, n = - 13

9 x^{2} - 37 = 6 x

72 - p = p^{2}

2 x^{2} = - 2

8 x^{2} + 1 = 22 x + 1

4 (x + 3)^{2} = 25 (x - 2)^{2}

What are the solutions to the equation n(n-7)=260 ?
The solutions to the equation n(n-7)=260 are n=20,n=-13
Find the zeros of n(n-7)=260
The zeros of n(n-7)=260 are n=20,n=-13