What are the solutions to the equation 28=x^2-4x+3x-2 ?

The solutions to the equation 28=x^2-4x+3x-2 are x=6,x=-5

Find the zeros of 28=x^2-4x+3x-2

The zeros of 28=x^2-4x+3x-2 are x=6,x=-5

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28 = x^{2} - 4 x + 3 x - 2

x = 6, x = - 5

Solution steps

28 = x^{2} - 4 x + 3 x - 2

Refine

28 = x^{2} - x - 2

Switch sides

x^{2} - x - 2 = 28

Move

28

to the left side

x^{2} - x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 30) = 11

x_{1, 2} = \frac{- ( - 1 ) \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 11}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 11}{2 \cdot 1}

x = \frac{- ( - 1 ) + 11}{2 \cdot 1} : 6

x = \frac{- ( - 1 ) - 11}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 6, x = - 5

- 6 - 12 n^{2} = - 396

m^{2} + 4 m - 3 = 0

(7 + 2 x) (3 + 2 x) = 77

(3 x + 4)^{2} = 16 (3 x + 4)

x^{2} = 15 x - 36

What are the solutions to the equation 28=x^2-4x+3x-2 ?
The solutions to the equation 28=x^2-4x+3x-2 are x=6,x=-5
Find the zeros of 28=x^2-4x+3x-2
The zeros of 28=x^2-4x+3x-2 are x=6,x=-5