What are the solutions to the equation y^2+24y+23=0 ?

The solutions to the equation y^2+24y+23=0 are y=-1,y=-23

Find the zeros of y^2+24y+23=0

The zeros of y^2+24y+23=0 are y=-1,y=-23

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y^{2} + 24 y + 23 = 0

y = - 1, y = - 23

Solution steps

y^{2} + 24 y + 23 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 1 \cdot 23}{2 \cdot 1}

2 4^{2} - 4 \cdot 1 \cdot 23 = 22

y_{1, 2} = \frac{- 24 \pm 22}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 24 + 22}{2 \cdot 1}, y_{2} = \frac{- 24 - 22}{2 \cdot 1}

y = \frac{- 24 + 22}{2 \cdot 1} : - 1

y = \frac{- 24 - 22}{2 \cdot 1} : - 23

The solutions to the quadratic equation are:

y = - 1, y = - 23

p^{2} + 5 p = 0

3 y (y - 4) = 5 (2 - y)

x^{2} + 5 x - 374 = 0

0 = (x + 2)^{2} - 25

x^{2} + 5 x + 7 = 3 x + 11

What are the solutions to the equation y^2+24y+23=0 ?
The solutions to the equation y^2+24y+23=0 are y=-1,y=-23
Find the zeros of y^2+24y+23=0
The zeros of y^2+24y+23=0 are y=-1,y=-23