What are the solutions to the equation p^2+5p=0 ?

The solutions to the equation p^2+5p=0 are p=0,p=-5

Find the zeros of p^2+5p=0

The zeros of p^2+5p=0 are p=0,p=-5

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p^{2} + 5 p = 0

p = 0, p = - 5

Solution steps

p^{2} + 5 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 0 = 5

p_{1, 2} = \frac{- 5 \pm 5}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 5 + 5}{2 \cdot 1}, p_{2} = \frac{- 5 - 5}{2 \cdot 1}

p = \frac{- 5 + 5}{2 \cdot 1} : 0

p = \frac{- 5 - 5}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

p = 0, p = - 5

3 y (y - 4) = 5 (2 - y)

x^{2} + 5 x - 374 = 0

0 = (x + 2)^{2} - 25

x^{2} + 5 x + 7 = 3 x + 11

6 a^{2} - 12 a - 18 = 0

What are the solutions to the equation p^2+5p=0 ?
The solutions to the equation p^2+5p=0 are p=0,p=-5
Find the zeros of p^2+5p=0
The zeros of p^2+5p=0 are p=0,p=-5