What are the solutions to the equation 0=(x+2)^2-25 ?

The solutions to the equation 0=(x+2)^2-25 are x=3,x=-7

Find the zeros of 0=(x+2)^2-25

The zeros of 0=(x+2)^2-25 are x=3,x=-7

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0 = (x + 2)^{2} - 25

x = 3, x = - 7

Solution steps

0 = (x + 2)^{2} - 25

Switch sides

(x + 2)^{2} - 25 = 0

Move

25

to the right side

(x + 2)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 25 : x = 3

Solve

x + 2 = - 25 : x = - 7

The solutions to the quadratic equation are:

x = 3, x = - 7

x^{2} + 5 x + 7 = 3 x + 11

6 a^{2} - 12 a - 18 = 0

3 x^{2} + 6 x - 6 = - 2 x^{2}

- 5 x^{2} + 101 x - 193 = 0

x^{2} - 18 x - 3 = 0

What are the solutions to the equation 0=(x+2)^2-25 ?
The solutions to the equation 0=(x+2)^2-25 are x=3,x=-7
Find the zeros of 0=(x+2)^2-25
The zeros of 0=(x+2)^2-25 are x=3,x=-7