What are the solutions to the equation x^2+5x+7=3x+11 ?

The solutions to the equation x^2+5x+7=3x+11 are x=-1+sqrt(5),x=-1-sqrt(5)

Find the zeros of x^2+5x+7=3x+11

The zeros of x^2+5x+7=3x+11 are x=-1+sqrt(5),x=-1-sqrt(5)

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x^{2} + 5 x + 7 = 3 x + 11

x = - 1 + 5, x = - 1 - 5

Decimal Notation

x = 1.23606 \dots, x = - 3.23606 \dots

Solution steps

x^{2} + 5 x + 7 = 3 x + 11

Move

11

to the left side

x^{2} + 5 x - 4 = 3 x

Move

3 x

to the left side

x^{2} + 2 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 4) = 25

x_{1, 2} = \frac{- 2 \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 5}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 5}{2 \cdot 1}

x = \frac{- 2 + 2 5}{2 \cdot 1} : - 1 + 5

x = \frac{- 2 - 2 5}{2 \cdot 1} : - 1 - 5

The solutions to the quadratic equation are:

x = - 1 + 5, x = - 1 - 5

6 a^{2} - 12 a - 18 = 0

3 x^{2} + 6 x - 6 = - 2 x^{2}

- 5 x^{2} + 101 x - 193 = 0

x^{2} - 18 x - 3 = 0

- 4 = (x - 3)^{2} - 4

What are the solutions to the equation x^2+5x+7=3x+11 ?
The solutions to the equation x^2+5x+7=3x+11 are x=-1+sqrt(5),x=-1-sqrt(5)
Find the zeros of x^2+5x+7=3x+11
The zeros of x^2+5x+7=3x+11 are x=-1+sqrt(5),x=-1-sqrt(5)