What are the solutions to the equation 6a^2-12a-18=0 ?

The solutions to the equation 6a^2-12a-18=0 are a=3,a=-1

Find the zeros of 6a^2-12a-18=0

The zeros of 6a^2-12a-18=0 are a=3,a=-1

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6 a^{2} - 12 a - 18 = 0

a = 3, a = - 1

Solution steps

6 a^{2} - 12 a - 18 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 6 ( - 18 )}{2 \cdot 6}

(- 12)^{2} - 4 \cdot 6 (- 18) = 24

a_{1, 2} = \frac{- ( - 12 ) \pm 24}{2 \cdot 6}

Separate the solutions

a_{1} = \frac{- ( - 12 ) + 24}{2 \cdot 6}, a_{2} = \frac{- ( - 12 ) - 24}{2 \cdot 6}

a = \frac{- ( - 12 ) + 24}{2 \cdot 6} : 3

a = \frac{- ( - 12 ) - 24}{2 \cdot 6} : - 1

The solutions to the quadratic equation are:

a = 3, a = - 1

3 x^{2} + 6 x - 6 = - 2 x^{2}

- 5 x^{2} + 101 x - 193 = 0

x^{2} - 18 x - 3 = 0

- 4 = (x - 3)^{2} - 4

2 x^{2} - 6 = - 206

What are the solutions to the equation 6a^2-12a-18=0 ?
The solutions to the equation 6a^2-12a-18=0 are a=3,a=-1
Find the zeros of 6a^2-12a-18=0
The zeros of 6a^2-12a-18=0 are a=3,a=-1