What are the solutions to the equation completesquare x^2+8x+10=0 ?

The solutions to the equation completesquare x^2+8x+10=0 are x=sqrt(6)-4,x=-sqrt(6)-4

Find the zeros of completesquare x^2+8x+10=0

The zeros of completesquare x^2+8x+10=0 are x=sqrt(6)-4,x=-sqrt(6)-4

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x^{2} + 8 x + 10 = 0

x = 6 - 4, x = - 6 - 4

Decimal Notation

x = - 1.55051 \dots, x = - 6.44948 \dots

Solution steps

x^{2} + 8 x + 10 = 0

Move

10

to the right side

x^{2} + 8 x = - 10

Rewrite in the form

(x + a)^{2} = b

(x + 4)^{2} = 6

For

the solutions are

f (x) = a, - a

Solve

x + 4 = 6 : x = 6 - 4

Solve

x + 4 = - 6 : x = - 6 - 4

The solutions to the quadratic equation are:

x = 6 - 4, x = - 6 - 4

4 x^{2} + 32 x = - 64

- x^{2} + 10 x - 22 = 0

1 + x^{2} = (- 10)^{2}

3 x - 6 + 6 x^{2} = 0

0 = 210 + 264 t + 0.5 (- 32.2) t^{2}

What are the solutions to the equation completesquare x^2+8x+10=0 ?
The solutions to the equation completesquare x^2+8x+10=0 are x=sqrt(6)-4,x=-sqrt(6)-4
Find the zeros of completesquare x^2+8x+10=0
The zeros of completesquare x^2+8x+10=0 are x=sqrt(6)-4,x=-sqrt(6)-4