What are the solutions to the equation 16x^2=40x-25 ?

The solutions to the equation 16x^2=40x-25 are x= 5/4

Find the zeros of 16x^2=40x-25

The zeros of 16x^2=40x-25 are x= 5/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16 x^{2} = 40 x - 25

x = \frac{5}{4}

Decimal Notation

x = 1.25

Solution steps

16 x^{2} = 40 x - 25

Move

25

to the left side

16 x^{2} + 25 = 40 x

Move

40 x

to the left side

16 x^{2} + 25 - 40 x = 0

Write in the standard form

a x^{2} + b x + c = 0

16 x^{2} - 40 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 16 \cdot 25}{2 \cdot 16}

(- 40)^{2} - 4 \cdot 16 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 40 ) \pm 0}{2 \cdot 16}

x = \frac{- ( - 40 )}{2 \cdot 16}

\frac{- ( - 40 )}{2 \cdot 16} = \frac{5}{4}

x = \frac{5}{4}

The solution to the quadratic equation is:

x = \frac{5}{4}

5 x^{2} - 10 x - 4 = 0

x^{2} + 1 2^{2} = 1 8^{2}

2 (x - 3)^{2} - 40 = 0

- x^{2} + 2 x - 3

y, x = z^{2} + y^{2}

What are the solutions to the equation 16x^2=40x-25 ?
The solutions to the equation 16x^2=40x-25 are x= 5/4
Find the zeros of 16x^2=40x-25
The zeros of 16x^2=40x-25 are x= 5/4