What are the solutions to the equation 5x^2-10x-4=0 ?

The solutions to the equation 5x^2-10x-4=0 are x=(5+3sqrt(5))/5 ,x=(5-3sqrt(5))/5

Find the zeros of 5x^2-10x-4=0

The zeros of 5x^2-10x-4=0 are x=(5+3sqrt(5))/5 ,x=(5-3sqrt(5))/5

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5 x^{2} - 10 x - 4 = 0

x = \frac{5 + 3 5}{5}, x = \frac{5 - 3 5}{5}

Decimal Notation

x = 2.34164 \dots, x = - 0.34164 \dots

Solution steps

5 x^{2} - 10 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 5 ( - 4 )}{2 \cdot 5}

(- 10)^{2} - 4 \cdot 5 (- 4) = 65

x_{1, 2} = \frac{- ( - 10 ) \pm 6 5}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 6 5}{2 \cdot 5}, x_{2} = \frac{- ( - 10 ) - 6 5}{2 \cdot 5}

x = \frac{- ( - 10 ) + 6 5}{2 \cdot 5} : \frac{5 + 3 5}{5}

x = \frac{- ( - 10 ) - 6 5}{2 \cdot 5} : \frac{5 - 3 5}{5}

The solutions to the quadratic equation are:

x = \frac{5 + 3 5}{5}, x = \frac{5 - 3 5}{5}

x^{2} + 1 2^{2} = 1 8^{2}

2 (x - 3)^{2} - 40 = 0

- x^{2} + 2 x - 3

y, x = z^{2} + y^{2}

2 s^{2} - 5 s = 3

What are the solutions to the equation 5x^2-10x-4=0 ?
The solutions to the equation 5x^2-10x-4=0 are x=(5+3sqrt(5))/5 ,x=(5-3sqrt(5))/5
Find the zeros of 5x^2-10x-4=0
The zeros of 5x^2-10x-4=0 are x=(5+3sqrt(5))/5 ,x=(5-3sqrt(5))/5