What are the solutions to the equation completesquare 2x^2+7x+3=0 ?

The solutions to the equation completesquare 2x^2+7x+3=0 are x=-1/2 ,x=-3

Find the zeros of completesquare 2x^2+7x+3=0

The zeros of completesquare 2x^2+7x+3=0 are x=-1/2 ,x=-3

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2 x^{2} + 7 x + 3 = 0

x = - \frac{1}{2}, x = - 3

Decimal Notation

x = - 0.5, x = - 3

Solution steps

2 x^{2} + 7 x + 3 = 0

Move

3

to the right side

2 x^{2} + 7 x = - 3

Divide both sides by

2

\frac{2 x ^{2} + 7 x}{2} = \frac{- 3}{2}

x^{2} + \frac{7 x}{2} = - \frac{3}{2}

Rewrite in the form

(x + a)^{2} = b

(x + \frac{7}{4})^{2} = \frac{25}{16}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{7}{4} = \frac{25}{16} : x = - \frac{1}{2}

Solve

x + \frac{7}{4} = - \frac{25}{16} : x = - 3

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - 3

(3 x + 2)^{2} - 5 (3 x + 2) = 0

b^{2} + 3 b - 10 = 0

- 16 x^{2} + 32 x = 0

37 n^{2} + 42 n - 20 = - 12 n^{2} + 7

x (x + 1) = 4 - (x + 2)^{2}

What are the solutions to the equation completesquare 2x^2+7x+3=0 ?
The solutions to the equation completesquare 2x^2+7x+3=0 are x=-1/2 ,x=-3
Find the zeros of completesquare 2x^2+7x+3=0
The zeros of completesquare 2x^2+7x+3=0 are x=-1/2 ,x=-3