What are the solutions to the equation 37n^2+42n-20=-12n^2+7 ?

The solutions to the equation 37n^2+42n-20=-12n^2+7 are n= 3/7 ,n=-9/7

Find the zeros of 37n^2+42n-20=-12n^2+7

The zeros of 37n^2+42n-20=-12n^2+7 are n= 3/7 ,n=-9/7

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37 n^{2} + 42 n - 20 = - 12 n^{2} + 7

n = \frac{3}{7}, n = - \frac{9}{7}

Decimal Notation

n = 0.42857 \dots, n = - 1.28571 \dots

Solution steps

37 n^{2} + 42 n - 20 = - 12 n^{2} + 7

Move

7

to the left side

37 n^{2} + 42 n - 27 = - 12 n^{2}

Move

12 n^{2}

to the left side

49 n^{2} + 42 n - 27 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 42 \pm 4 2 ^{2} - 4 \cdot 49 ( - 27 )}{2 \cdot 49}

4 2^{2} - 4 \cdot 49 (- 27) = 84

n_{1, 2} = \frac{- 42 \pm 84}{2 \cdot 49}

Separate the solutions

n_{1} = \frac{- 42 + 84}{2 \cdot 49}, n_{2} = \frac{- 42 - 84}{2 \cdot 49}

n = \frac{- 42 + 84}{2 \cdot 49} : \frac{3}{7}

n = \frac{- 42 - 84}{2 \cdot 49} : - \frac{9}{7}

The solutions to the quadratic equation are:

n = \frac{3}{7}, n = - \frac{9}{7}

x (x + 1) = 4 - (x + 2)^{2}

3 x^{2} + 24 x + 32 = 0

x, 2 x^{2} y = 5

x, 3 x^{2} = 225

3 x^{2} - 3 x = 4 - 6 x + 2 x^{2}

What are the solutions to the equation 37n^2+42n-20=-12n^2+7 ?
The solutions to the equation 37n^2+42n-20=-12n^2+7 are n= 3/7 ,n=-9/7
Find the zeros of 37n^2+42n-20=-12n^2+7
The zeros of 37n^2+42n-20=-12n^2+7 are n= 3/7 ,n=-9/7