What are the solutions to the equation -16x^2+32x=0 ?

The solutions to the equation -16x^2+32x=0 are x=0,x=2

Find the zeros of -16x^2+32x=0

The zeros of -16x^2+32x=0 are x=0,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 16 x^{2} + 32 x = 0

x = 0, x = 2

Solution steps

- 16 x^{2} + 32 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

3 2^{2} - 4 (- 16) \cdot 0 = 32

x_{1, 2} = \frac{- 32 \pm 32}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 32 + 32}{2 ( - 16 )}, x_{2} = \frac{- 32 - 32}{2 ( - 16 )}

x = \frac{- 32 + 32}{2 ( - 16 )} : 0

x = \frac{- 32 - 32}{2 ( - 16 )} : 2

The solutions to the quadratic equation are:

x = 0, x = 2

37 n^{2} + 42 n - 20 = - 12 n^{2} + 7

x (x + 1) = 4 - (x + 2)^{2}

3 x^{2} + 24 x + 32 = 0

x, 2 x^{2} y = 5

x, 3 x^{2} = 225

What are the solutions to the equation -16x^2+32x=0 ?
The solutions to the equation -16x^2+32x=0 are x=0,x=2
Find the zeros of -16x^2+32x=0
The zeros of -16x^2+32x=0 are x=0,x=2