What are the solutions to the equation 3x^2+24x+32=0 ?

The solutions to the equation 3x^2+24x+32=0 are x=(4(sqrt(3)-3))/3 ,x=-(4(3+sqrt(3)))/3

Find the zeros of 3x^2+24x+32=0

The zeros of 3x^2+24x+32=0 are x=(4(sqrt(3)-3))/3 ,x=-(4(3+sqrt(3)))/3

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3 x^{2} + 24 x + 32 = 0

x = \frac{4 ( 3 - 3 )}{3}, x = - \frac{4 ( 3 + 3 )}{3}

Solution steps

3 x^{2} + 24 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 3 \cdot 32}{2 \cdot 3}

2 4^{2} - 4 \cdot 3 \cdot 32 = 83

x_{1, 2} = \frac{- 24 \pm 8 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 24 + 8 3}{2 \cdot 3}, x_{2} = \frac{- 24 - 8 3}{2 \cdot 3}

x = \frac{- 24 + 8 3}{2 \cdot 3} : \frac{4 ( 3 - 3 )}{3}

x = \frac{- 24 - 8 3}{2 \cdot 3} : - \frac{4 ( 3 + 3 )}{3}

The solutions to the quadratic equation are:

x = \frac{4 ( 3 - 3 )}{3}, x = - \frac{4 ( 3 + 3 )}{3}

x, 2 x^{2} y = 5

x, 3 x^{2} = 225

3 x^{2} - 3 x = 4 - 6 x + 2 x^{2}

x^{2} + 4 x + 7 = 0

3 x^{2} - 12 x - 11

What are the solutions to the equation 3x^2+24x+32=0 ?
The solutions to the equation 3x^2+24x+32=0 are x=(4(sqrt(3)-3))/3 ,x=-(4(3+sqrt(3)))/3
Find the zeros of 3x^2+24x+32=0
The zeros of 3x^2+24x+32=0 are x=(4(sqrt(3)-3))/3 ,x=-(4(3+sqrt(3)))/3