What are the solutions to the equation solvefor x,2x^2y=5 ?

The solutions to the equation solvefor x,2x^2y=5 are x=sqrt(5/(2y)),x=-sqrt(5/(2y));\quad y\ne 0

Find the zeros of solvefor x,2x^2y=5

The zeros of solvefor x,2x^2y=5 are x=sqrt(5/(2y)),x=-sqrt(5/(2y));\quad y\ne 0

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solve for

x, 2 x^{2} y = 5

x = \frac{5}{2 y}, x = - \frac{5}{2 y}; y \neq = 0

Solution steps

2 x^{2} y = 5

Divide both sides by

2 y; y \neq = 0

x^{2} = \frac{5}{2 y}; y \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{5}{2 y}, x = - \frac{5}{2 y}; y \neq = 0

x, 3 x^{2} = 225

3 x^{2} - 3 x = 4 - 6 x + 2 x^{2}

x^{2} + 4 x + 7 = 0

3 x^{2} - 12 x - 11

A = x^{2} + 12 x + 27

What are the solutions to the equation solvefor x,2x^2y=5 ?
The solutions to the equation solvefor x,2x^2y=5 are x=sqrt(5/(2y)),x=-sqrt(5/(2y));\quad y\ne 0
Find the zeros of solvefor x,2x^2y=5
The zeros of solvefor x,2x^2y=5 are x=sqrt(5/(2y)),x=-sqrt(5/(2y));\quad y\ne 0