What are the solutions to the equation 3x^2-3x=4-6x+2x^2 ?

The solutions to the equation 3x^2-3x=4-6x+2x^2 are x=-4,x=1

Find the zeros of 3x^2-3x=4-6x+2x^2

The zeros of 3x^2-3x=4-6x+2x^2 are x=-4,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 3 x = 4 - 6 x + 2 x^{2}

x = - 4, x = 1

Solution steps

3 x^{2} - 3 x = 4 - 6 x + 2 x^{2}

Switch sides

4 - 6 x + 2 x^{2} = 3 x^{2} - 3 x

Move

3 x

to the left side

2 x^{2} - 3 x + 4 = 3 x^{2}

Move

3 x^{2}

to the left side

- x^{2} - 3 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 1 ) \cdot 4}{2 ( - 1 )}

(- 3)^{2} - 4 (- 1) \cdot 4 = 5

x_{1, 2} = \frac{- ( - 3 ) \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 5}{2 ( - 1 )}, x_{2} = \frac{- ( - 3 ) - 5}{2 ( - 1 )}

x = \frac{- ( - 3 ) + 5}{2 ( - 1 )} : - 4

x = \frac{- ( - 3 ) - 5}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

x = - 4, x = 1

x^{2} + 4 x + 7 = 0

3 x^{2} - 12 x - 11

A = x^{2} + 12 x + 27

x^{2} - 6 x + 15 = 10

0.02 x^{2} - 0.3 x = 20

What are the solutions to the equation 3x^2-3x=4-6x+2x^2 ?
The solutions to the equation 3x^2-3x=4-6x+2x^2 are x=-4,x=1
Find the zeros of 3x^2-3x=4-6x+2x^2
The zeros of 3x^2-3x=4-6x+2x^2 are x=-4,x=1