What are the solutions to the equation -6x^2+9x+24=0 ?

The solutions to the equation -6x^2+9x+24=0 are x=-(-3+sqrt(73))/4 ,x=(3+sqrt(73))/4

Find the zeros of -6x^2+9x+24=0

The zeros of -6x^2+9x+24=0 are x=-(-3+sqrt(73))/4 ,x=(3+sqrt(73))/4

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- 6 x^{2} + 9 x + 24 = 0

x = - \frac{- 3 + 73}{4}, x = \frac{3 + 73}{4}

Solution steps

- 6 x^{2} + 9 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 6 ) \cdot 24}{2 ( - 6 )}

9^{2} - 4 (- 6) \cdot 24 = 373

x_{1, 2} = \frac{- 9 \pm 3 73}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 9 + 3 73}{2 ( - 6 )}, x_{2} = \frac{- 9 - 3 73}{2 ( - 6 )}

x = \frac{- 9 + 3 73}{2 ( - 6 )} : - \frac{- 3 + 73}{4}

x = \frac{- 9 - 3 73}{2 ( - 6 )} : \frac{3 + 73}{4}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 73}{4}, x = \frac{3 + 73}{4}

- 4 m^{2} - 12 m + 3 = 0

x^{2} - 20 = - 8 x

- x^{2} + 2 x = - 3

(x + 1)^{2} - \frac{x + 1}{2} = 18

x^{2} + 7^{2} = 1 2^{2}

What are the solutions to the equation -6x^2+9x+24=0 ?
The solutions to the equation -6x^2+9x+24=0 are x=-(-3+sqrt(73))/4 ,x=(3+sqrt(73))/4
Find the zeros of -6x^2+9x+24=0
The zeros of -6x^2+9x+24=0 are x=-(-3+sqrt(73))/4 ,x=(3+sqrt(73))/4