What are the solutions to the equation -4m^2-12m+3=0 ?

The solutions to the equation -4m^2-12m+3=0 are m=-(3+2sqrt(3))/2 ,m=(2sqrt(3)-3)/2

Find the zeros of -4m^2-12m+3=0

The zeros of -4m^2-12m+3=0 are m=-(3+2sqrt(3))/2 ,m=(2sqrt(3)-3)/2

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- 4 m^{2} - 12 m + 3 = 0

m = - \frac{3 + 2 3}{2}, m = \frac{2 3 - 3}{2}

Decimal Notation

m = - 3.23205 \dots, m = 0.23205 \dots

Solution steps

- 4 m^{2} - 12 m + 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 4 ) \cdot 3}{2 ( - 4 )}

(- 12)^{2} - 4 (- 4) \cdot 3 = 83

m_{1, 2} = \frac{- ( - 12 ) \pm 8 3}{2 ( - 4 )}

Separate the solutions

m_{1} = \frac{- ( - 12 ) + 8 3}{2 ( - 4 )}, m_{2} = \frac{- ( - 12 ) - 8 3}{2 ( - 4 )}

m = \frac{- ( - 12 ) + 8 3}{2 ( - 4 )} : - \frac{3 + 2 3}{2}

m = \frac{- ( - 12 ) - 8 3}{2 ( - 4 )} : \frac{2 3 - 3}{2}

The solutions to the quadratic equation are:

m = - \frac{3 + 2 3}{2}, m = \frac{2 3 - 3}{2}

x^{2} - 20 = - 8 x

- x^{2} + 2 x = - 3

(x + 1)^{2} - \frac{x + 1}{2} = 18

x^{2} + 7^{2} = 1 2^{2}

16 x^{2} - 40 = 0

What are the solutions to the equation -4m^2-12m+3=0 ?
The solutions to the equation -4m^2-12m+3=0 are m=-(3+2sqrt(3))/2 ,m=(2sqrt(3)-3)/2
Find the zeros of -4m^2-12m+3=0
The zeros of -4m^2-12m+3=0 are m=-(3+2sqrt(3))/2 ,m=(2sqrt(3)-3)/2