What are the solutions to the equation 1/4 (x+2)^2-2=3 ?

The solutions to the equation 1/4 (x+2)^2-2=3 are x=2sqrt(5)-2,x=-2sqrt(5)-2

Find the zeros of 1/4 (x+2)^2-2=3

The zeros of 1/4 (x+2)^2-2=3 are x=2sqrt(5)-2,x=-2sqrt(5)-2

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\frac{1}{4} (x + 2)^{2} - 2 = 3

x = 25 - 2, x = - 25 - 2

Solution steps

\frac{1}{4} (x + 2)^{2} - 2 = 3

Move

2

to the right side

\frac{1}{4} (x + 2)^{2} = 5

Multiply both sides by

4

(x + 2)^{2} = 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 20 : x = 25 - 2

Solve

x + 2 = - 20 : x = - 25 - 2

The solutions to the quadratic equation are:

x = 25 - 2, x = - 25 - 2

2 \cdot x^{2} + x = 15

4 y - 20 y^{2} = 0

y, x - y^{2} = 1

7 x - 3 + 8 x^{2} = 7 + 4 x^{2} - x

x (x - 6) + 5 (x + 8) = - 2 (3 x - 32)

What are the solutions to the equation 1/4 (x+2)^2-2=3 ?
The solutions to the equation 1/4 (x+2)^2-2=3 are x=2sqrt(5)-2,x=-2sqrt(5)-2
Find the zeros of 1/4 (x+2)^2-2=3
The zeros of 1/4 (x+2)^2-2=3 are x=2sqrt(5)-2,x=-2sqrt(5)-2