What are the solutions to the equation solvefor x,2x^2-4x=0 ?

The solutions to the equation solvefor x,2x^2-4x=0 are x=2,x=0

Find the zeros of solvefor x,2x^2-4x=0

The zeros of solvefor x,2x^2-4x=0 are x=2,x=0

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x, 2 x^{2} - 4 x = 0

x = 2, x = 0

Solution steps

2 x^{2} - 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 \cdot 0 = 4

x_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 2}

x = \frac{- ( - 4 ) + 4}{2 \cdot 2} : 2

x = \frac{- ( - 4 ) - 4}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = 2, x = 0

12 x^{2} + 12 = 0

- 6 x^{2} + 24 x - 504 = 0

15 x^{2} - 23 x - 28 = 0

150 = 50 x + x^{2}

j (x) = x^{2} - x + 1, j (2 a)

What are the solutions to the equation solvefor x,2x^2-4x=0 ?
The solutions to the equation solvefor x,2x^2-4x=0 are x=2,x=0
Find the zeros of solvefor x,2x^2-4x=0
The zeros of solvefor x,2x^2-4x=0 are x=2,x=0