What are the solutions to the equation x(x-10)+21=0 ?

The solutions to the equation x(x-10)+21=0 are x=7,x=3

Find the zeros of x(x-10)+21=0

The zeros of x(x-10)+21=0 are x=7,x=3

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x (x - 10) + 21 = 0

x = 7, x = 3

Solution steps

x (x - 10) + 21 = 0

Expand

x (x - 10) + 21 : x^{2} - 10 x + 21

x^{2} - 10 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 21 = 4

x_{1, 2} = \frac{- ( - 10 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 4}{2 \cdot 1}

x = \frac{- ( - 10 ) + 4}{2 \cdot 1} : 7

x = \frac{- ( - 10 ) - 4}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 7, x = 3

6 x^{2} - 3 x = 0

7 x^{2} - 15 x + 8 = 0

2 t (t + 1) = 7

r, y = 4 π r^{2}

x^{2} - 3 \cdot (- 10) = 0

What are the solutions to the equation x(x-10)+21=0 ?
The solutions to the equation x(x-10)+21=0 are x=7,x=3
Find the zeros of x(x-10)+21=0
The zeros of x(x-10)+21=0 are x=7,x=3