What are the solutions to the equation 15x^2-9x+12=0 ?

The solutions to the equation 15x^2-9x+12=0 are x= 3/10+i(sqrt(71))/(10),x= 3/10-i(sqrt(71))/(10)

Find the zeros of 15x^2-9x+12=0

The zeros of 15x^2-9x+12=0 are x= 3/10+i(sqrt(71))/(10),x= 3/10-i(sqrt(71))/(10)

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15 x^{2} - 9 x + 12 = 0

x = \frac{3}{10} + i \frac{71}{10}, x = \frac{3}{10} - i \frac{71}{10}

Solution steps

15 x^{2} - 9 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 15 \cdot 12}{2 \cdot 15}

Simplify

(- 9)^{2} - 4 \cdot 15 \cdot 12 : 371 i

x_{1, 2} = \frac{- ( - 9 ) \pm 3 71 i}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 3 71 i}{2 \cdot 15}, x_{2} = \frac{- ( - 9 ) - 3 71 i}{2 \cdot 15}

x = \frac{- ( - 9 ) + 3 71 i}{2 \cdot 15} : \frac{3}{10} + i \frac{71}{10}

x = \frac{- ( - 9 ) - 3 71 i}{2 \cdot 15} : \frac{3}{10} - i \frac{71}{10}

The solutions to the quadratic equation are:

x = \frac{3}{10} + i \frac{71}{10}, x = \frac{3}{10} - i \frac{71}{10}

5 x^{2} + 11 x - 1 = 0

x^{2} + 4 x = 0

- x^{2} + 8 x - 5

x^{2} + 22 x - 5 = 0

x^{2} - 126 = 2 x + 1

What are the solutions to the equation 15x^2-9x+12=0 ?
The solutions to the equation 15x^2-9x+12=0 are x= 3/10+i(sqrt(71))/(10),x= 3/10-i(sqrt(71))/(10)
Find the zeros of 15x^2-9x+12=0
The zeros of 15x^2-9x+12=0 are x= 3/10+i(sqrt(71))/(10),x= 3/10-i(sqrt(71))/(10)