What are the solutions to the equation (2x-5)^2-81=0 ?

The solutions to the equation (2x-5)^2-81=0 are x=7,x=-2

Find the zeros of (2x-5)^2-81=0

The zeros of (2x-5)^2-81=0 are x=7,x=-2

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(2 x - 5)^{2} - 81 = 0

x = 7, x = - 2

Solution steps

(2 x - 5)^{2} - 81 = 0

Move

81

to the right side

(2 x - 5)^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 5 = 81 : x = 7

Solve

2 x - 5 = - 81 : x = - 2

The solutions to the quadratic equation are:

x = 7, x = - 2

4 x^{2} + 23 x - 72 = 0

x + 30 = 4 x^{2} + 20 x + 25

16 - 24 x + 9 x^{2} = 0

3 q^{2} - 136 q + 1300 = 0

12 x^{2} + 10 x + 2 = 0

What are the solutions to the equation (2x-5)^2-81=0 ?
The solutions to the equation (2x-5)^2-81=0 are x=7,x=-2
Find the zeros of (2x-5)^2-81=0
The zeros of (2x-5)^2-81=0 are x=7,x=-2