What are the solutions to the equation 16-24x+9x^2=0 ?

The solutions to the equation 16-24x+9x^2=0 are x= 4/3

Find the zeros of 16-24x+9x^2=0

The zeros of 16-24x+9x^2=0 are x= 4/3

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16 - 24 x + 9 x^{2} = 0

x = \frac{4}{3}

Solution steps

16 - 24 x + 9 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

9 x^{2} - 24 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 9 \cdot 16}{2 \cdot 9}

(- 24)^{2} - 4 \cdot 9 \cdot 16 = 0

x_{1, 2} = \frac{- ( - 24 ) \pm 0}{2 \cdot 9}

x = \frac{- ( - 24 )}{2 \cdot 9}

\frac{- ( - 24 )}{2 \cdot 9} = \frac{4}{3}

x = \frac{4}{3}

The solution to the quadratic equation is:

x = \frac{4}{3}

3 q^{2} - 136 q + 1300 = 0

12 x^{2} + 10 x + 2 = 0

5 x^{2} - x - 4 = 0

6 x^{2} + 3 = 7 x

x^{2} + 4 x + 3 = 195

What are the solutions to the equation 16-24x+9x^2=0 ?
The solutions to the equation 16-24x+9x^2=0 are x= 4/3
Find the zeros of 16-24x+9x^2=0
The zeros of 16-24x+9x^2=0 are x= 4/3