What are the solutions to the equation 4x^2+23x-72=0 ?

The solutions to the equation 4x^2+23x-72=0 are x= 9/4 ,x=-8

Find the zeros of 4x^2+23x-72=0

The zeros of 4x^2+23x-72=0 are x= 9/4 ,x=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 23 x - 72 = 0

x = \frac{9}{4}, x = - 8

Solution steps

4 x^{2} + 23 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 4 ( - 72 )}{2 \cdot 4}

2 3^{2} - 4 \cdot 4 (- 72) = 41

x_{1, 2} = \frac{- 23 \pm 41}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 23 + 41}{2 \cdot 4}, x_{2} = \frac{- 23 - 41}{2 \cdot 4}

x = \frac{- 23 + 41}{2 \cdot 4} : \frac{9}{4}

x = \frac{- 23 - 41}{2 \cdot 4} : - 8

The solutions to the quadratic equation are:

x = \frac{9}{4}, x = - 8

x + 30 = 4 x^{2} + 20 x + 25

16 - 24 x + 9 x^{2} = 0

3 q^{2} - 136 q + 1300 = 0

12 x^{2} + 10 x + 2 = 0

5 x^{2} - x - 4 = 0

What are the solutions to the equation 4x^2+23x-72=0 ?
The solutions to the equation 4x^2+23x-72=0 are x= 9/4 ,x=-8
Find the zeros of 4x^2+23x-72=0
The zeros of 4x^2+23x-72=0 are x= 9/4 ,x=-8