What are the solutions to the equation 12x^2+10x+2=0 ?

The solutions to the equation 12x^2+10x+2=0 are x=-1/3 ,x=-1/2

Find the zeros of 12x^2+10x+2=0

The zeros of 12x^2+10x+2=0 are x=-1/3 ,x=-1/2

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12 x^{2} + 10 x + 2 = 0

x = - \frac{1}{3}, x = - \frac{1}{2}

Solution steps

12 x^{2} + 10 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 12 \cdot 2}{2 \cdot 12}

1 0^{2} - 4 \cdot 12 \cdot 2 = 2

x_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 10 + 2}{2 \cdot 12}, x_{2} = \frac{- 10 - 2}{2 \cdot 12}

x = \frac{- 10 + 2}{2 \cdot 12} : - \frac{1}{3}

x = \frac{- 10 - 2}{2 \cdot 12} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - \frac{1}{2}

5 x^{2} - x - 4 = 0

6 x^{2} + 3 = 7 x

x^{2} + 4 x + 3 = 195

3 x^{2} + 4 x - 32 = 0

x, 7 x^{2} + 8 x - 9 = 10

What are the solutions to the equation 12x^2+10x+2=0 ?
The solutions to the equation 12x^2+10x+2=0 are x=-1/3 ,x=-1/2
Find the zeros of 12x^2+10x+2=0
The zeros of 12x^2+10x+2=0 are x=-1/3 ,x=-1/2