What are the solutions to the equation completesquare 5x^2-x-4=0 ?

The solutions to the equation completesquare 5x^2-x-4=0 are x=1,x=-4/5

Find the zeros of completesquare 5x^2-x-4=0

The zeros of completesquare 5x^2-x-4=0 are x=1,x=-4/5

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5 x^{2} - x - 4 = 0

x = 1, x = - \frac{4}{5}

Decimal Notation

x = 1, x = - 0.8

Solution steps

5 x^{2} - x - 4 = 0

Move

4

to the right side

5 x^{2} - x = 4

Divide both sides by

5

\frac{5 x ^{2} - x}{5} = \frac{4}{5}

x^{2} - \frac{x}{5} = \frac{4}{5}

Rewrite in the form

(x + a)^{2} = b

(x - \frac{1}{10})^{2} = \frac{81}{100}

For

the solutions are

f (x) = a, - a

Solve

x - \frac{1}{10} = \frac{81}{100} : x = 1

Solve

x - \frac{1}{10} = - \frac{81}{100} : x = - \frac{4}{5}

The solutions to the quadratic equation are:

x = 1, x = - \frac{4}{5}

6 x^{2} + 3 = 7 x

x^{2} + 4 x + 3 = 195

3 x^{2} + 4 x - 32 = 0

x, 7 x^{2} + 8 x - 9 = 10

x^{2} - 7 = - 3 x^{2}

What are the solutions to the equation completesquare 5x^2-x-4=0 ?
The solutions to the equation completesquare 5x^2-x-4=0 are x=1,x=-4/5
Find the zeros of completesquare 5x^2-x-4=0
The zeros of completesquare 5x^2-x-4=0 are x=1,x=-4/5