What are the solutions to the equation 49x^2-3=13 ?

The solutions to the equation 49x^2-3=13 are x= 4/7 ,x=-4/7

Find the zeros of 49x^2-3=13

The zeros of 49x^2-3=13 are x= 4/7 ,x=-4/7

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49 x^{2} - 3 = 13

x = \frac{4}{7}, x = - \frac{4}{7}

Decimal Notation

x = 0.57142 \dots, x = - 0.57142 \dots

Solution steps

49 x^{2} - 3 = 13

Move

3

to the right side

49 x^{2} = 16

Divide both sides by

49

x^{2} = \frac{16}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{16}{49}, x = - \frac{16}{49}

\frac{16}{49} = \frac{4}{7}

- \frac{16}{49} = - \frac{4}{7}

x = \frac{4}{7}, x = - \frac{4}{7}

2 x \cdot (x - 3) - x \cdot (x - 3) = 0

x^{2} - 2 x + 1 - x = - 2 x^{2} + x

5 (x - 2)^{2} = - 20

- x^{2} + 7 x + 3 = 0

x (2 x + 3) - 5 = 6 x

What are the solutions to the equation 49x^2-3=13 ?
The solutions to the equation 49x^2-3=13 are x= 4/7 ,x=-4/7
Find the zeros of 49x^2-3=13
The zeros of 49x^2-3=13 are x= 4/7 ,x=-4/7