What are the solutions to the equation 5(x-2)^2=-20 ?

The solutions to the equation 5(x-2)^2=-20 are x=2i+2,x=-2i+2

Find the zeros of 5(x-2)^2=-20

The zeros of 5(x-2)^2=-20 are x=2i+2,x=-2i+2

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5 (x - 2)^{2} = - 20

x = 2 i + 2, x = - 2 i + 2

Solution steps

5 (x - 2)^{2} = - 20

Divide both sides by

5

(x - 2)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = - 4 : x = 2 i + 2

Solve

x - 2 = - - 4 : x = - 2 i + 2

The solutions to the quadratic equation are:

x = 2 i + 2, x = - 2 i + 2

- x^{2} + 7 x + 3 = 0

x (2 x + 3) - 5 = 6 x

x^{2} + 20 x - 2400 = 0

3 (- 3)^{2} + 2 y^{2} = 36

- 2 x^{2} + 8 x + 2 = 0

What are the solutions to the equation 5(x-2)^2=-20 ?
The solutions to the equation 5(x-2)^2=-20 are x=2i+2,x=-2i+2
Find the zeros of 5(x-2)^2=-20
The zeros of 5(x-2)^2=-20 are x=2i+2,x=-2i+2