What are the solutions to the equation x^2-25x+156=0 ?

The solutions to the equation x^2-25x+156=0 are x=13,x=12

Find the zeros of x^2-25x+156=0

The zeros of x^2-25x+156=0 are x=13,x=12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 25 x + 156 = 0

x = 13, x = 12

Solution steps

x^{2} - 25 x + 156 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 1 \cdot 156}{2 \cdot 1}

(- 25)^{2} - 4 \cdot 1 \cdot 156 = 1

x_{1, 2} = \frac{- ( - 25 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 25 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 25 ) - 1}{2 \cdot 1}

x = \frac{- ( - 25 ) + 1}{2 \cdot 1} : 13

x = \frac{- ( - 25 ) - 1}{2 \cdot 1} : 12

The solutions to the quadratic equation are:

x = 13, x = 12

6 (x - 1) = x^{2} + x

2 = x^{2} - 3 x - 8

4 = \frac{4}{3} (x - 6) 34 (x - 6)

t, S = \frac{1}{2} a t^{2}

- 9 x^{2} + 24 x - 16 = 0

What are the solutions to the equation x^2-25x+156=0 ?
The solutions to the equation x^2-25x+156=0 are x=13,x=12
Find the zeros of x^2-25x+156=0
The zeros of x^2-25x+156=0 are x=13,x=12