What are the solutions to the equation solvefor y,x=2-y^2 ?

The solutions to the equation solvefor y,x=2-y^2 are y=sqrt(-x+2),y=-sqrt(-x+2)

Find the zeros of solvefor y,x=2-y^2

The zeros of solvefor y,x=2-y^2 are y=sqrt(-x+2),y=-sqrt(-x+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

y, x = 2 - y^{2}

y = - x + 2, y = - - x + 2

Solution steps

x = 2 - y^{2}

Switch sides

2 - y^{2} = x

Move

2

to the right side

- y^{2} = x - 2

Divide both sides by

- 1

y^{2} = - x + 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - x + 2, y = - - x + 2

9 n^{2} + 3 = 67

y, x^{2} + (y - 3)^{2} = 9

2 x^{2} + 9 x - 15 = 0

2 n^{2} = 12 - 5 n

c^{2} - 9 c + 20 = 0

What are the solutions to the equation solvefor y,x=2-y^2 ?
The solutions to the equation solvefor y,x=2-y^2 are y=sqrt(-x+2),y=-sqrt(-x+2)
Find the zeros of solvefor y,x=2-y^2
The zeros of solvefor y,x=2-y^2 are y=sqrt(-x+2),y=-sqrt(-x+2)