What are the solutions to the equation 9n^2+3=67 ?

The solutions to the equation 9n^2+3=67 are n= 8/3 ,n=-8/3

Find the zeros of 9n^2+3=67

The zeros of 9n^2+3=67 are n= 8/3 ,n=-8/3

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9 n^{2} + 3 = 67

n = \frac{8}{3}, n = - \frac{8}{3}

Decimal Notation

n = 2.66666 \dots, n = - 2.66666 \dots

Solution steps

9 n^{2} + 3 = 67

Move

3

to the right side

9 n^{2} = 64

Divide both sides by

9

n^{2} = \frac{64}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = \frac{64}{9}, n = - \frac{64}{9}

\frac{64}{9} = \frac{8}{3}

- \frac{64}{9} = - \frac{8}{3}

n = \frac{8}{3}, n = - \frac{8}{3}

y, x^{2} + (y - 3)^{2} = 9

2 x^{2} + 9 x - 15 = 0

2 n^{2} = 12 - 5 n

c^{2} - 9 c + 20 = 0

x^{2} + (3 x)^{2} = 16

What are the solutions to the equation 9n^2+3=67 ?
The solutions to the equation 9n^2+3=67 are n= 8/3 ,n=-8/3
Find the zeros of 9n^2+3=67
The zeros of 9n^2+3=67 are n= 8/3 ,n=-8/3