What are the solutions to the equation 2n^2=12-5n ?

The solutions to the equation 2n^2=12-5n are n= 3/2 ,n=-4

Find the zeros of 2n^2=12-5n

The zeros of 2n^2=12-5n are n= 3/2 ,n=-4

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2 n^{2} = 12 - 5 n

n = \frac{3}{2}, n = - 4

Decimal Notation

n = 1.5, n = - 4

Solution steps

2 n^{2} = 12 - 5 n

Move

5 n

to the left side

2 n^{2} + 5 n = 12

Move

12

to the left side

2 n^{2} + 5 n - 12 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 12) = 11

n_{1, 2} = \frac{- 5 \pm 11}{2 \cdot 2}

Separate the solutions

n_{1} = \frac{- 5 + 11}{2 \cdot 2}, n_{2} = \frac{- 5 - 11}{2 \cdot 2}

n = \frac{- 5 + 11}{2 \cdot 2} : \frac{3}{2}

n = \frac{- 5 - 11}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

n = \frac{3}{2}, n = - 4

c^{2} - 9 c + 20 = 0

x^{2} + (3 x)^{2} = 16

2 x^{2} + 5 x = 25

x^{2} = 2 x + 7

(x + 3) (x - 1) = - 3 x + 4

What are the solutions to the equation 2n^2=12-5n ?
The solutions to the equation 2n^2=12-5n are n= 3/2 ,n=-4
Find the zeros of 2n^2=12-5n
The zeros of 2n^2=12-5n are n= 3/2 ,n=-4