What are the solutions to the equation y^2-15y=-54 ?

The solutions to the equation y^2-15y=-54 are y=9,y=6

Find the zeros of y^2-15y=-54

The zeros of y^2-15y=-54 are y=9,y=6

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y^{2} - 15 y = - 54

y = 9, y = 6

Solution steps

y^{2} - 15 y = - 54

Move

54

to the left side

y^{2} - 15 y + 54 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 54}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 54 = 3

y_{1, 2} = \frac{- ( - 15 ) \pm 3}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 15 ) + 3}{2 \cdot 1}, y_{2} = \frac{- ( - 15 ) - 3}{2 \cdot 1}

y = \frac{- ( - 15 ) + 3}{2 \cdot 1} : 9

y = \frac{- ( - 15 ) - 3}{2 \cdot 1} : 6

The solutions to the quadratic equation are:

y = 9, y = 6

1 + 10 x - 0.9 x^{2} = 0

x^{2} + 5 = 8

4 w^{2} - 7 w + 6 = 5

(5 - x)^{2} = 0

- 2 s^{2} + 8 s - 4 = 0

What are the solutions to the equation y^2-15y=-54 ?
The solutions to the equation y^2-15y=-54 are y=9,y=6
Find the zeros of y^2-15y=-54
The zeros of y^2-15y=-54 are y=9,y=6