What are the solutions to the equation 6c^2-2c-3=1 ?

The solutions to the equation 6c^2-2c-3=1 are c=1,c=-2/3

Find the zeros of 6c^2-2c-3=1

The zeros of 6c^2-2c-3=1 are c=1,c=-2/3

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6 c^{2} - 2 c - 3 = 1

c = 1, c = - \frac{2}{3}

Decimal Notation

c = 1, c = - 0.66666 \dots

Solution steps

6 c^{2} - 2 c - 3 = 1

Move

1

to the left side

6 c^{2} - 2 c - 4 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 6 ( - 4 )}{2 \cdot 6}

(- 2)^{2} - 4 \cdot 6 (- 4) = 10

c_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 6}

Separate the solutions

c_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 6}, c_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 6}

c = \frac{- ( - 2 ) + 10}{2 \cdot 6} : 1

c = \frac{- ( - 2 ) - 10}{2 \cdot 6} : - \frac{2}{3}

The solutions to the quadratic equation are:

c = 1, c = - \frac{2}{3}

x = x^{2} - 3

42 (p^{2} - 1) = 13 p

x (x + 3) = 180

z^{2} + 14 z - 1 = 0

- 3 x (4 x + 2) = 2 x + 1

What are the solutions to the equation 6c^2-2c-3=1 ?
The solutions to the equation 6c^2-2c-3=1 are c=1,c=-2/3
Find the zeros of 6c^2-2c-3=1
The zeros of 6c^2-2c-3=1 are c=1,c=-2/3