What are the solutions to the equation x(x+3)=180 ?

The solutions to the equation x(x+3)=180 are x=12,x=-15

Find the zeros of x(x+3)=180

The zeros of x(x+3)=180 are x=12,x=-15

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x (x + 3) = 180

x = 12, x = - 15

Solution steps

x (x + 3) = 180

Expand

x (x + 3) : x^{2} + 3 x

x^{2} + 3 x = 180

Move

180

to the left side

x^{2} + 3 x - 180 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 180 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 180) = 27

x_{1, 2} = \frac{- 3 \pm 27}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 27}{2 \cdot 1}, x_{2} = \frac{- 3 - 27}{2 \cdot 1}

x = \frac{- 3 + 27}{2 \cdot 1} : 12

x = \frac{- 3 - 27}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = 12, x = - 15

z^{2} + 14 z - 1 = 0

- 3 x (4 x + 2) = 2 x + 1

4 x^{2} - 72 x = - 68

- 5 x - x^{2} = 84

(6 - x) (2 - x) + 5 = 0

What are the solutions to the equation x(x+3)=180 ?
The solutions to the equation x(x+3)=180 are x=12,x=-15
Find the zeros of x(x+3)=180
The zeros of x(x+3)=180 are x=12,x=-15