What are the solutions to the equation (3n-1)^2=64 ?

The solutions to the equation (3n-1)^2=64 are n=3,n=-7/3

Find the zeros of (3n-1)^2=64

The zeros of (3n-1)^2=64 are n=3,n=-7/3

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(3 n - 1)^{2} = 64

n = 3, n = - \frac{7}{3}

Decimal Notation

n = 3, n = - 2.33333 \dots

Solution steps

(3 n - 1)^{2} = 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 n - 1 = 64 : n = 3

Solve

3 n - 1 = - 64 : n = - \frac{7}{3}

The solutions to the quadratic equation are:

n = 3, n = - \frac{7}{3}

f^{2} - 3 f + 2 = 0

2 x^{2} + 5 = 103

a x^{2} + 2 x + 6 = 0

\frac{1}{2} (x + 2)^{2} + 5 = 3

0 = 2 x^{2} - 11 x - 40

What are the solutions to the equation (3n-1)^2=64 ?
The solutions to the equation (3n-1)^2=64 are n=3,n=-7/3
Find the zeros of (3n-1)^2=64
The zeros of (3n-1)^2=64 are n=3,n=-7/3