What are the solutions to the equation 4x^2-64x+76=0 ?

The solutions to the equation 4x^2-64x+76=0 are x=8+3sqrt(5),x=8-3sqrt(5)

Find the zeros of 4x^2-64x+76=0

The zeros of 4x^2-64x+76=0 are x=8+3sqrt(5),x=8-3sqrt(5)

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4 x^{2} - 64 x + 76 = 0

x = 8 + 35, x = 8 - 35

Decimal Notation

x = 14.70820 \dots, x = 1.29179 \dots

Solution steps

4 x^{2} - 64 x + 76 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 64 ) \pm ( - 64 ) ^{2} - 4 \cdot 4 \cdot 76}{2 \cdot 4}

(- 64)^{2} - 4 \cdot 4 \cdot 76 = 245

x_{1, 2} = \frac{- ( - 64 ) \pm 24 5}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 64 ) + 24 5}{2 \cdot 4}, x_{2} = \frac{- ( - 64 ) - 24 5}{2 \cdot 4}

x = \frac{- ( - 64 ) + 24 5}{2 \cdot 4} : 8 + 35

x = \frac{- ( - 64 ) - 24 5}{2 \cdot 4} : 8 - 35

The solutions to the quadratic equation are:

x = 8 + 35, x = 8 - 35

x^{2} + 4 \cdot (- 12) = 0

2 u^{2} + 5 u - 3 = 0

2 x^{2} + 14 x = 16

n^{2} - n = 6

x^{2} - 14 x - 4 = 0

What are the solutions to the equation 4x^2-64x+76=0 ?
The solutions to the equation 4x^2-64x+76=0 are x=8+3sqrt(5),x=8-3sqrt(5)
Find the zeros of 4x^2-64x+76=0
The zeros of 4x^2-64x+76=0 are x=8+3sqrt(5),x=8-3sqrt(5)