What are the solutions to the equation -4+1/2 x^2=0 ?

The solutions to the equation -4+1/2 x^2=0 are x=2sqrt(2),x=-2sqrt(2)

Find the zeros of -4+1/2 x^2=0

The zeros of -4+1/2 x^2=0 are x=2sqrt(2),x=-2sqrt(2)

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- 4 + \frac{1}{2} x^{2} = 0

x = 22, x = - 22

Decimal Notation

x = 2.82842 \dots, x = - 2.82842 \dots

Solution steps

- 4 + \frac{1}{2} x^{2} = 0

Move

4

to the right side

\frac{1}{2} x^{2} = 4

Multiply both sides by

2

x^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 8, x = - 8

8 = 22

- 8 = - 22

x = 22, x = - 22

s, r = t s^{2} + 3

- 6 x^{2} - 12 x + 48 = 0

1 - 0.8 x - 0.16 x^{2} = 0

12 x^{2} + 8 x = 20

a^{2} + 4 0^{2} = 4 1^{2}

What are the solutions to the equation -4+1/2 x^2=0 ?
The solutions to the equation -4+1/2 x^2=0 are x=2sqrt(2),x=-2sqrt(2)
Find the zeros of -4+1/2 x^2=0
The zeros of -4+1/2 x^2=0 are x=2sqrt(2),x=-2sqrt(2)