What are the solutions to the equation (x-3)(x+6)=1 ?

The solutions to the equation (x-3)(x+6)=1 are x=(-3+sqrt(85))/2 ,x=(-3-sqrt(85))/2

Find the zeros of (x-3)(x+6)=1

The zeros of (x-3)(x+6)=1 are x=(-3+sqrt(85))/2 ,x=(-3-sqrt(85))/2

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(x - 3) (x + 6) = 1

x = \frac{- 3 + 85}{2}, x = \frac{- 3 - 85}{2}

Decimal Notation

x = 3.10977 \dots, x = - 6.10977 \dots

Solution steps

(x - 3) (x + 6) = 1

Expand

(x - 3) (x + 6) : x^{2} + 3 x - 18

x^{2} + 3 x - 18 = 1

Move

1

to the left side

x^{2} + 3 x - 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 19 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 19) = 85

x_{1, 2} = \frac{- 3 \pm 85}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 85}{2 \cdot 1}, x_{2} = \frac{- 3 - 85}{2 \cdot 1}

x = \frac{- 3 + 85}{2 \cdot 1} : \frac{- 3 + 85}{2}

x = \frac{- 3 - 85}{2 \cdot 1} : \frac{- 3 - 85}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 85}{2}, x = \frac{- 3 - 85}{2}

4 x^{2} - x - 33 = 0

4 a^{2} = - 16

4 = 3 x^{2} - x

d^{2} + d - 19 = 4 d

m^{2} + 11 m = - 30

What are the solutions to the equation (x-3)(x+6)=1 ?
The solutions to the equation (x-3)(x+6)=1 are x=(-3+sqrt(85))/2 ,x=(-3-sqrt(85))/2
Find the zeros of (x-3)(x+6)=1
The zeros of (x-3)(x+6)=1 are x=(-3+sqrt(85))/2 ,x=(-3-sqrt(85))/2