What are the solutions to the equation 9z^2-3z=20 ?

The solutions to the equation 9z^2-3z=20 are z= 5/3 ,z=-4/3

Find the zeros of 9z^2-3z=20

The zeros of 9z^2-3z=20 are z= 5/3 ,z=-4/3

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9 z^{2} - 3 z = 20

z = \frac{5}{3}, z = - \frac{4}{3}

Decimal Notation

z = 1.66666 \dots, z = - 1.33333 \dots

Solution steps

9 z^{2} - 3 z = 20

Move

20

to the left side

9 z^{2} - 3 z - 20 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 9 ( - 20 )}{2 \cdot 9}

(- 3)^{2} - 4 \cdot 9 (- 20) = 27

z_{1, 2} = \frac{- ( - 3 ) \pm 27}{2 \cdot 9}

Separate the solutions

z_{1} = \frac{- ( - 3 ) + 27}{2 \cdot 9}, z_{2} = \frac{- ( - 3 ) - 27}{2 \cdot 9}

z = \frac{- ( - 3 ) + 27}{2 \cdot 9} : \frac{5}{3}

z = \frac{- ( - 3 ) - 27}{2 \cdot 9} : - \frac{4}{3}

The solutions to the quadratic equation are:

z = \frac{5}{3}, z = - \frac{4}{3}

2 (x + 3)^{2} = 9

4 r^{2} + 3 r + 6 = 357

144 x^{2} - 9 = 0

0 = x^{2} + 5 x - 14

x^{2} = 12 x - 32

What are the solutions to the equation 9z^2-3z=20 ?
The solutions to the equation 9z^2-3z=20 are z= 5/3 ,z=-4/3
Find the zeros of 9z^2-3z=20
The zeros of 9z^2-3z=20 are z= 5/3 ,z=-4/3