What are the solutions to the equation w^2-4=12 ?

The solutions to the equation w^2-4=12 are w=4,w=-4

Find the zeros of w^2-4=12

The zeros of w^2-4=12 are w=4,w=-4

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w^{2} - 4 = 12

w = 4, w = - 4

Solution steps

w^{2} - 4 = 12

Move

4

to the right side

w^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

w = 16, w = - 16

16 = 4

- 16 = - 4

w = 4, w = - 4

5 p^{2} + 11 p + 6 = 0

(2 x + 4) (x - 3) = 0

7 x^{2} - x^{2} = 168

x^{2} + 10 x = 2

z^{2} + z - 6 = 0

What are the solutions to the equation w^2-4=12 ?
The solutions to the equation w^2-4=12 are w=4,w=-4
Find the zeros of w^2-4=12
The zeros of w^2-4=12 are w=4,w=-4