What are the solutions to the equation x^2-6x+9=-3 ?

The solutions to the equation x^2-6x+9=-3 are x=3+sqrt(3)i,x=3-sqrt(3)i

Find the zeros of x^2-6x+9=-3

The zeros of x^2-6x+9=-3 are x=3+sqrt(3)i,x=3-sqrt(3)i

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x^{2} - 6 x + 9 = - 3

x = 3 + 3 i, x = 3 - 3 i

Solution steps

x^{2} - 6 x + 9 = - 3

Move

3

to the left side

x^{2} - 6 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 12 : 23 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 3 i}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 3 i}{2 \cdot 1} : 3 + 3 i

x = \frac{- ( - 6 ) - 2 3 i}{2 \cdot 1} : 3 - 3 i

The solutions to the quadratic equation are:

x = 3 + 3 i, x = 3 - 3 i

- 9 x^{2} + 153 x - 144 = 0

2 x^{2} + 4 x + 30 = 0

x^{2} + 2 x - 0.5 = 0

(x + 2)^{2} + x^{2} = 74

(3 y + 17)^{2} = 50

What are the solutions to the equation x^2-6x+9=-3 ?
The solutions to the equation x^2-6x+9=-3 are x=3+sqrt(3)i,x=3-sqrt(3)i
Find the zeros of x^2-6x+9=-3
The zeros of x^2-6x+9=-3 are x=3+sqrt(3)i,x=3-sqrt(3)i