What are the solutions to the equation x^2+8x=13 ?

The solutions to the equation x^2+8x=13 are x=-4+sqrt(29),x=-4-sqrt(29)

Find the zeros of x^2+8x=13

The zeros of x^2+8x=13 are x=-4+sqrt(29),x=-4-sqrt(29)

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x^{2} + 8 x = 13

x = - 4 + 29, x = - 4 - 29

Decimal Notation

x = 1.38516 \dots, x = - 9.38516 \dots

Solution steps

x^{2} + 8 x = 13

Move

13

to the left side

x^{2} + 8 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 13 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 13) = 229

x_{1, 2} = \frac{- 8 \pm 2 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 29}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 29}{2 \cdot 1}

x = \frac{- 8 + 2 29}{2 \cdot 1} : - 4 + 29

x = \frac{- 8 - 2 29}{2 \cdot 1} : - 4 - 29

The solutions to the quadratic equation are:

x = - 4 + 29, x = - 4 - 29

5 x^{2} + 10 x + 25 = 0

2 x^{2} + 10 x = 2

800 = \frac{n}{2} (30 + (n - 1) 10)

(8 + x) \cdot 3 x - (8 + x) \cdot 7 = 0

c^{2} - 32 = 0

What are the solutions to the equation x^2+8x=13 ?
The solutions to the equation x^2+8x=13 are x=-4+sqrt(29),x=-4-sqrt(29)
Find the zeros of x^2+8x=13
The zeros of x^2+8x=13 are x=-4+sqrt(29),x=-4-sqrt(29)