What are the solutions to the equation 16x^2-57x+49=0 ?

The solutions to the equation 16x^2-57x+49=0 are x=(57+sqrt(113))/(32),x=(57-sqrt(113))/(32)

Find the zeros of 16x^2-57x+49=0

The zeros of 16x^2-57x+49=0 are x=(57+sqrt(113))/(32),x=(57-sqrt(113))/(32)

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16 x^{2} - 57 x + 49 = 0

x = \frac{57 + 113}{32}, x = \frac{57 - 113}{32}

Decimal Notation

x = 2.11344 \dots, x = 1.44905 \dots

Solution steps

16 x^{2} - 57 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 57 ) \pm ( - 57 ) ^{2} - 4 \cdot 16 \cdot 49}{2 \cdot 16}

(- 57)^{2} - 4 \cdot 16 \cdot 49 = 113

x_{1, 2} = \frac{- ( - 57 ) \pm 113}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 57 ) + 113}{2 \cdot 16}, x_{2} = \frac{- ( - 57 ) - 113}{2 \cdot 16}

x = \frac{- ( - 57 ) + 113}{2 \cdot 16} : \frac{57 + 113}{32}

x = \frac{- ( - 57 ) - 113}{2 \cdot 16} : \frac{57 - 113}{32}

The solutions to the quadratic equation are:

x = \frac{57 + 113}{32}, x = \frac{57 - 113}{32}

1 x^{2} + 3 x - 4 = 0

x, 4 x^{2} - y^{2} = c

x^{2} + 4 x - 120 = 0

12 x^{2} + 8 = 20 x

3 t^{2} - 12 t - 36 = 0

What are the solutions to the equation 16x^2-57x+49=0 ?
The solutions to the equation 16x^2-57x+49=0 are x=(57+sqrt(113))/(32),x=(57-sqrt(113))/(32)
Find the zeros of 16x^2-57x+49=0
The zeros of 16x^2-57x+49=0 are x=(57+sqrt(113))/(32),x=(57-sqrt(113))/(32)