What are the solutions to the equation 9p^2+272p+944=0 ?

The solutions to the equation 9p^2+272p+944=0 are p=-4,p=-236/9

Find the zeros of 9p^2+272p+944=0

The zeros of 9p^2+272p+944=0 are p=-4,p=-236/9

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9 p^{2} + 272 p + 944 = 0

p = - 4, p = - \frac{236}{9}

Decimal Notation

p = - 4, p = - 26.22222 \dots

Solution steps

9 p^{2} + 272 p + 944 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 272 \pm 27 2 ^{2} - 4 \cdot 9 \cdot 944}{2 \cdot 9}

27 2^{2} - 4 \cdot 9 \cdot 944 = 200

p_{1, 2} = \frac{- 272 \pm 200}{2 \cdot 9}

Separate the solutions

p_{1} = \frac{- 272 + 200}{2 \cdot 9}, p_{2} = \frac{- 272 - 200}{2 \cdot 9}

p = \frac{- 272 + 200}{2 \cdot 9} : - 4

p = \frac{- 272 - 200}{2 \cdot 9} : - \frac{236}{9}

The solutions to the quadratic equation are:

p = - 4, p = - \frac{236}{9}

2 x^{2} + 5 x = 1200

(1 + x)^{2} + x^{2} = 11

12 x + 9 = - 4 x^{2}

5 t^{2} - 11 t = 12

x + 3 x + 1.5 x 44 x - 2 = 169

What are the solutions to the equation 9p^2+272p+944=0 ?
The solutions to the equation 9p^2+272p+944=0 are p=-4,p=-236/9
Find the zeros of 9p^2+272p+944=0
The zeros of 9p^2+272p+944=0 are p=-4,p=-236/9