What are the solutions to the equation 5x^2+10x+50=0 ?

The solutions to the equation 5x^2+10x+50=0 are x=-1+3i,x=-1-3i

Find the zeros of 5x^2+10x+50=0

The zeros of 5x^2+10x+50=0 are x=-1+3i,x=-1-3i

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5 x^{2} + 10 x + 50 = 0

x = - 1 + 3 i, x = - 1 - 3 i

Solution steps

5 x^{2} + 10 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 5 \cdot 50}{2 \cdot 5}

Simplify

1 0^{2} - 4 \cdot 5 \cdot 50 : 30 i

x_{1, 2} = \frac{- 10 \pm 30 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 10 + 30 i}{2 \cdot 5}, x_{2} = \frac{- 10 - 30 i}{2 \cdot 5}

x = \frac{- 10 + 30 i}{2 \cdot 5} : - 1 + 3 i

x = \frac{- 10 - 30 i}{2 \cdot 5} : - 1 - 3 i

The solutions to the quadratic equation are:

x = - 1 + 3 i, x = - 1 - 3 i

h^{2} = 2^{2} + 2 2.3

3 x^{2} + 6 x - 7

x^{2} = 225

5 x^{2} + 4 x = 2 x^{2} + 7 x

x^{2} + 6 x + 3^{2} = 8 + 9

What are the solutions to the equation 5x^2+10x+50=0 ?
The solutions to the equation 5x^2+10x+50=0 are x=-1+3i,x=-1-3i
Find the zeros of 5x^2+10x+50=0
The zeros of 5x^2+10x+50=0 are x=-1+3i,x=-1-3i