What are the solutions to the equation 3k^2-18k-21=0 ?

The solutions to the equation 3k^2-18k-21=0 are k=7,k=-1

Find the zeros of 3k^2-18k-21=0

The zeros of 3k^2-18k-21=0 are k=7,k=-1

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3 k^{2} - 18 k - 21 = 0

k = 7, k = - 1

Solution steps

3 k^{2} - 18 k - 21 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 3 ( - 21 )}{2 \cdot 3}

(- 18)^{2} - 4 \cdot 3 (- 21) = 24

k_{1, 2} = \frac{- ( - 18 ) \pm 24}{2 \cdot 3}

Separate the solutions

k_{1} = \frac{- ( - 18 ) + 24}{2 \cdot 3}, k_{2} = \frac{- ( - 18 ) - 24}{2 \cdot 3}

k = \frac{- ( - 18 ) + 24}{2 \cdot 3} : 7

k = \frac{- ( - 18 ) - 24}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

k = 7, k = - 1

3 x^{2} - 12 x + 3 = 0

∣ x - 1 ∣ > ∣ 2 x - 1 ∣

x^{2} - x - 72 = 0

x^{2} + 3 x + 8 = 0

(x + 8)^{2} + (x - 6)^{2} = (x + 12)^{2}

What are the solutions to the equation 3k^2-18k-21=0 ?
The solutions to the equation 3k^2-18k-21=0 are k=7,k=-1
Find the zeros of 3k^2-18k-21=0
The zeros of 3k^2-18k-21=0 are k=7,k=-1